3m^2+8m=35

Solution for 3m^2+8m=35 equation:

3m^2+8m=35

We move all terms to the left:

3m^2+8m-(35)=0

a = 3; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·3·(-35)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-22}{2*3}=\frac{-30}{6}
=-5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+22}{2*3}=\frac{14}{6}
=2+1/3
$